erdos_849

Is it true that, for every integer $t\geq1$, there is some integer $a$ such that ${n \choose k} = a$ with $1\leq k \le \frac{n}{2}$ has exactly $t$ solutions?

theorem erdos_849 : answer(sorry) ↔
    ∀ t ≥ 1, ∃ a : ℕ,
      {n : ℕ | ∃ k ≥ 1, 2 * k ≤ n ∧ choose n k = a}.ncard = t

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